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Go Back   Webmaster Forums > Website Developement / Programming > MySQL Forums

MySQL Forums Share Your Ideas and Tips about MYSQL. Ask questions about MYSQL. Table Design and Much More...

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Old 08-08-2006, 07:53 AM
Kierra Kierra is offline
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Default code not executed!

Hello people,
i have this script working on old versions of MySQL but Not Working After line 81. can you please help me on this one?

here is the code that is not executed with me .

// Delete User And Add It To Paid Table
$sql="select * from next where id='$id2'";
$res=mysql_query($sql) or die ("MySQL Problem : " . mysql_error());
$row=mysql_fetch_array($res) or die("MySQL Problem : " . mysql_error());
$user3=@$row[user];
$egold3=@$row[egold];
$spot3=@$row[spot];
$email3=@$row[email];
$sqll="INSERT INTO `paid` VALUES ('' , '$user3' , '$egold3' , '$spot3' , '$email3')";
mysql_query($sqll) or die ("MySQL Problem : " . mysql_error());
$sql2="DELETE from `next` where id='$id2' limit 1";
mysql_query($sql2) or die ("MySQL Problem : " . mysql_error()); -- This message may have been cut off and the rest will only be shown to members. To become a member, click here --
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